{"id":36,"date":"2024-04-04T07:50:47","date_gmt":"2024-04-04T04:50:47","guid":{"rendered":"https:\/\/sisu.ut.ee\/keemiaabc\/64-arvutused-reaktsioonivorrandi-pohjal\/"},"modified":"2024-06-13T11:12:56","modified_gmt":"2024-06-13T08:12:56","slug":"64-arvutused-reaktsioonivorrandi-pohjal","status":"publish","type":"page","link":"https:\/\/sisu.ut.ee\/keemiaabc\/64-arvutused-reaktsioonivorrandi-pohjal\/","title":{"rendered":"6.4. Arvutused reaktsiooniv\u00f5rrandi p\u00f5hjal"},"content":{"rendered":"<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Keemias tuleb sageli teha arvutusi reaktsiooniv\u00f5rrandite p\u00f5hjal. Selleks tuleks eelnevalt kirjutada rekatsiooniv\u00f5rrand ja see ka tasakaalustada. Reaktsiooniv\u00f5rrandis olevad kordajad n\u00e4itavad reageerivate ja tekkivate ainete hulka moolides. Kuidas reaktsiooniv\u00f5rrandi kordajaid arvutustes kasutada ning milliseid arvutusi reaktsiooniv\u00f5rrandi alusel v\u00f5ib teha, saad vaadata j\u00e4rgmisest videost.<\/span><\/span><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><\/p><div class=\"ratio ratio-16x9 mb-3\"><div class=\"video-placeholder-wrapper video-placeholder-wrapper--16x9\">\n\t\t\t    <div class=\"video-placeholder d-flex justify-content-center align-items-center\">\n\t\t\t        <div class=\"overlay text-white p-2 w-100 text-center d-block justify-content-center align-items-center\">\n\t\t\t            <div>Kolmandate osapoolte sisu n\u00e4gemiseks palun n\u00f5ustu k\u00fcpsistega.<\/div>\n\t\t\t            <button class=\"btn btn-secondary btn-sm mt-1 consent-change\">Muuda n\u00f5usolekut<\/button>\n\t\t\t        <\/div>\n\t\t\t    <\/div>\n\t\t\t<\/div>\n<\/div>\n<h6 style=\"margin: 12pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Allikas:\u00a0<\/span><\/span><\/span><a title=\"\" href=\"https:\/\/youtu.be\/m-orM45x_iw\" target=\"_blank\" rel=\"noopener\" data-url=\"https:\/\/youtu.be\/m-orM45x_iw\">https:\/\/youtu.be\/m-orM45x_iw<\/a><\/h6>\n<h5 style=\"margin: 12pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Reaktsiooniv\u00f5rrandi kordajad v\u00e4ljendavad reageerivate ainete hulkade suhet moolides.<\/span><\/span><\/span><\/h5>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Selleks, et teha arvutusi reaktsiooniv\u00f5rrandite p\u00f5hjal, tuleb k\u00f5igepealt aru saada, et reaktsiooniv\u00f5rrandi kordajad v\u00e4ljendavad reageerivate ainete hulkade suhet moolides.<\/span><\/span><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">V\u00f5ttes aluseks lihtsa keemilise reaktsiooni, kus hapniku ja vesiniku \u00fchinemisel tekib vesi, saame kirja panna j\u00e4rgneva reaktsiooniv\u00f5rrandi:<\/span><\/span><\/span><\/p>\n<p style=\"margin: 12pt 0cm 12pt 40px;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2H<sub>2<\/sub> + O<sub>2<\/sub><\/span><\/span><span lang=\"et\"><span style=\"line-height: 150%;\"> \u2192 2H<\/span><\/span><sub><span lang=\"et\"><span style=\"line-height: 150%;\">2<\/span><\/span><\/sub><span lang=\"et\"><span style=\"line-height: 150%;\">O<\/span><\/span><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">See reaktsiooniv\u00f5rrand n\u00e4itab, et kaks mooli vesinikku reageerib \u00fche mooli hapnikuga ning tekib kaks mooli vett. Oletame, et meil on vaja saada aga 10 mooli vett. Tasakaalus reaktsiooniv\u00f5rrandi kohaselt on meil aga kaks mooli vett. Selleks, et saada 10 mooli vett, tuleb v\u00f5tta viiekordne kogus aineid. Seega saame \u00f6elda, et 10 mooli vee saamiseks on vaja:<\/span><\/span><\/span><\/p>\n<p style=\"margin: 12pt 0cm 12pt 40px;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">vesinikku 5 <\/span><span style=\"background: white;\"><span style=\"line-height: 150%;\">$\\times $ <\/span><\/span><span style=\"line-height: 150%;\">2 mol = 10 mol<\/span><\/span><\/span><\/p>\n<p style=\"margin: 12pt 0cm 12pt 40px;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">hapnikku 5 <\/span><span style=\"background: white;\"><span style=\"line-height: 150%;\">$\\times $<\/span><\/span><span style=\"line-height: 150%;\"> 1 mol = 5 mol<\/span><\/span><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Arvutus\u00fclesannete lihtsamaks lahendamiseks v\u00f5id juhinduda j\u00e4rgnevatest sammudest:<\/span><\/span><\/span><\/p>\n<ol>\n<li>Loe \u00fclesande tekst m\u00f5ttega l\u00e4bi ning pane paika l\u00e4hteained ja saadused.<\/li>\n<li>Kirjuta tekstile vastav reaktsiooniv\u00f5rrand ning tasakaalusta see.<\/li>\n<li>Kirjuta v\u00e4lja andmed ja otsitav.<\/li>\n<li>L\u00e4hteainete mass v\u00f5i ruumala tuleb \u00fcmber arvutada moolideks.<\/li>\n<li>Kasutades moolsuhet (reaktsiooniv\u00f5rrandi kordajaid) leia otsitava aine hulk moolides.<\/li>\n<li>Vajadusel arvuta otsitava aine moolid \u00fcmber massiks v\u00f5i ruumalaks.<\/li>\n<\/ol>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Tuleta varasemast meelde ka j\u00e4rgmised valemid, mida\u00a0arvutustes v\u00f5ib vaja minna. Ainehulga leidmise valemid:<\/span><\/span><\/span><\/p>\n<p style=\"text-align: center;\">$n=\\frac{m}{M}$<\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\"><i>n\u00a0<\/i>\u2013 ainehulga t\u00e4his (\u00fchik mool, l\u00fchend mol)<\/span><\/span><\/span><br>\n<span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">m <\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">\u2013 aine massi (\u00fchik gramm) <\/span><\/span><\/span><br>\n<span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">M <\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">\u2013 molaarmass (\u00fchik g\/mol). <\/span><\/span><\/span><\/p>\n<p style=\"text-align: center;\">$n=\\frac{N}{N_{A}}$<\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">n\u00a0<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">\u2013 ainehulga t\u00e4his (\u00fchik mool, l\u00fchend mol)<\/span><\/span><\/span><br>\n<span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">N\u00a0<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">\u2013 aineosakeste arv (\u00fchik aineosakene)<\/span><\/span><\/span><br>\n<span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">N<sub>A<\/sub> \u2013 Avogadro arv, mille v\u00e4\u00e4rtus on 6,02 <\/span><\/span><span lang=\"et\"><span style=\"background: white;\"><span style=\"line-height: 150%;\">\u00d7<\/span><\/span><\/span><span lang=\"et\"><span style=\"line-height: 150%;\">10<sup>23<\/sup>\u00a0aineosakest\/mol. <\/span><\/span><\/span><\/p>\n<p style=\"margin: 12pt 0cm; text-align: center;\">$n=\\frac{V}{V_{m}}$<\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">n\u00a0<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">\u2013 ainehulga t\u00e4his (\u00fchik mool, l\u00fchend mol)<\/span><\/span><\/span><br>\n<span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">V\u00a0<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">\u2013 aine ruumala (\u00fchik dm<sup>3<\/sup>)<\/span><\/span><\/span><br>\n<span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">V<\/span><\/span><\/i><sub><span lang=\"et\"><span style=\"line-height: 150%;\">m<\/span><\/span><\/sub><span lang=\"et\"><span style=\"line-height: 150%;\"> \u2013 molaarruumala (v\u00e4\u00e4rtus 22,4 dm<sup>3<\/sup>\/mol)<\/span><\/span><\/span><\/p>\n<h2>N\u00e4idis\u00fclesanne 1. Moolilt moolile \u00fcleminek<\/h2>\n<table class=\"table table-hover\" style=\"width: 100%;\" border=\"0\" cellspacing=\"1\" cellpadding=\"1\">\n<tbody>\n<tr>\n<td style=\"width: 50%;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">1. Loeme teksti l\u00e4bi ning paneme kirja l\u00e4hteained, milleks hetkel on vesinik ja hapnik.<\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Mitu mooli hapniku kulub reageerimiseks 12 mol vesinikuga?<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2. Kirjutame ja tasakaalustame tekstile vastava reaktsiooniv\u00f5rrandi.<\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2H<sub>2<\/sub> + O<sub>2<\/sub><\/span><\/span><span lang=\"et\"><span style=\"line-height: 150%;\"> \u2192 2H<\/span><\/span><sub><span lang=\"et\"><span style=\"line-height: 150%;\">2<\/span><\/span><\/sub><span lang=\"et\"><span style=\"line-height: 150%;\">O<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">\u00a03. Kirjutame v\u00e4lja andmed ja otsitava.<\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><i><u><span lang=\"et\"><span style=\"line-height: 150%;\">n<\/span><\/span><\/u><\/i><u><span lang=\"et\"><span style=\"line-height: 150%;\">(H<sub>2<\/sub>) = 12 mol<\/span><\/span><\/u><\/span>\n<p><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">n<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">(O<sub>2<\/sub>) = ?<\/span><\/span><\/span><\/p><\/td>\n<\/tr>\n<tr>\n<td>4. <span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Antud hetkel on vaja leida \u00fche aine moolid teise aine moolide j\u00e4rgi. Seega ei pea \u00fcle minema ei massile ega ruumalale, vaid lihtsalt arvestama moolsuhet. <\/span><\/span><\/span><\/td>\n<td>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Tasakaalustatud reaktsiooniv\u00f5rrandist on n\u00e4ha, et H<sub>2<\/sub> ja O<sub>2<\/sub> moolsuhe on 2:1. Kirjutame v\u00e4lja j\u00e4rgneva seose:<\/span><\/span><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span lang=\"et\"><span style=\"line-height: 115%;\">\u00a02 \u2013 1<\/span><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span lang=\"et\"><span style=\"line-height: 115%;\">12 mol \u2013 x mol<\/span><\/span><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td><span lang=\"et\"><span style=\"line-height: 115%;\">5. Avaldame hapniku moolid.<\/span><\/span><\/td>\n<td>$n(O_{2})=\\frac{12\\ mol\\times 1}{2}= 6\\ mol$\n<p><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Kui Sa ei soovi seost v\u00e4lja kirjutada, v\u00f5id ka m\u00f5elda, et vesinikku on hetkel 2 korda rohkem kui hapniku, j\u00e4relikult peab olema hapniku 2 korda v\u00e4hem v\u00f5rreldes vesinikuga ning sellest tulenevalt saad arvutada<i> n<\/i>(O<sub>2<\/sub>) = 12 mol \/ 2 = 6 mol<\/span><\/span><\/span><\/p><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><\/p><div class=\"accordion mb-3\">\n        <div class=\"accordion-item accordion-item--white\">\n        <h2 class=\"accordion-header\" id=\"accordion-69dc48804e49e-heading\">\n            <button class=\"accordion-button collapsed\" type=\"button\" data-bs-toggle=\"collapse\" data-bs-target=\"#accordion-69dc48804e49e-collapse\" aria-expanded=\"true\" aria-controls=\"accordion-69dc48804e49e-collapse\">\u00dclesanne 1<\/button>\n        <\/h2>\n        <div id=\"accordion-69dc48804e49e-collapse\" class=\"accordion-collapse collapse\" aria-labelledby=\"accordion-69dc48804e49e-heading\">\n            <div class=\"accordion-body\">\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><div class=\"video-placeholder-wrapper video-placeholder-wrapper--fixed\" style=\"height: 385px;\">\n\t\t\t    <div class=\"video-placeholder d-flex justify-content-center align-items-center\">\n\t\t\t        <div class=\"overlay text-white p-2 w-100 text-center d-block justify-content-center align-items-center\">\n\t\t\t            <div>Kolmandate osapoolte sisu n\u00e4gemiseks palun n\u00f5ustu k\u00fcpsistega.<\/div>\n\t\t\t            <button class=\"btn btn-secondary btn-sm mt-1 consent-change\">Muuda n\u00f5usolekut<\/button>\n\t\t\t        <\/div>\n\t\t\t    <\/div>\n\t\t\t<\/div>\n<script src=\"https:\/\/sisu.ut.ee\/wp-content\/plugins\/h5p\/h5p-php-library\/js\/h5p-resizer.js\" charset=\"UTF-8\"><\/script><\/p><\/div>\n        <\/div>\n        <\/div>\n    <\/div>\n<h2>N\u00e4idis\u00fclesanne 2. Moolilt massile \u00fcleminek<\/h2>\n<table class=\"table table-hover\" style=\"width: 100%;\" border=\"0\" cellspacing=\"1\" cellpadding=\"1\">\n<tbody>\n<tr>\n<td style=\"width: 50%;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">1. Loeme teksti l\u00e4bi ning paneme kirja, et nii vesinik kui ka hapnik on hetkel l\u00e4hteained ning tekib vesi.<\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Mitu grammi vett tekib, kui hapnik reageerib 2 mol vesinikuga?<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2. Kirjutame ja tasakaalustame tekstile vastava reaktsiooniv\u00f5rrandi.<\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2H<sub>2<\/sub> + O<sub>2<\/sub><\/span><\/span><span lang=\"et\"><span style=\"line-height: 150%;\"> \u2192 2H<\/span><\/span><sub><span lang=\"et\"><span style=\"line-height: 150%;\">2<\/span><\/span><\/sub><span lang=\"et\"><span style=\"line-height: 150%;\">O<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">\u00a03. Kirjutame v\u00e4lja andmed ja otsitava.<\/span><\/span><\/span><\/td>\n<td>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><i><u><span lang=\"et\"><span style=\"line-height: 150%;\">n<\/span><\/span><\/u><\/i><u><span lang=\"et\"><span style=\"line-height: 150%;\">(H<sub>2<\/sub>) = 2 mol<\/span><\/span><\/u><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">m<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">(H<sub>2<\/sub>O) = ?<\/span><\/span><\/span><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">\u00a04. Antud hetkel on vaja leida \u00fche aine mass teise aine moolide j\u00e4rgi. Seega tuleb k\u00f5igepealt leida vee moolid, arvestades moolsuhet. <\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Tasakaalustatud reaktsiooniv\u00f5rrandist on n\u00e4ha, et H<sub>2<\/sub> ja H<sub>2<\/sub>O moolsuhe on 2:2 ehk moolide arvud on v\u00f5rdsed.\u00a0 Sellest saame j\u00e4reldada, et ka <i>n<\/i>(H<sub>2<\/sub>O) = 2 mol.<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">\u00a05. Meie k\u00e4est k\u00fcsiti aga vee massi. Moolid ja massid sidus j\u00e4rgnev valem:<\/span><\/span><\/span><\/p>\n<\/td>\n<td>$n=\\frac{m}{M}$<\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">6. Avaldame valemist massi.<\/span><\/span><\/span><\/td>\n<td><i><span lang=\"et\"><span style=\"line-height: 115%;\">m<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 115%;\"> = <i>n <\/i>$\\times $ <i>M<\/i><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span lang=\"et\"><span style=\"line-height: 115%;\">7. Leiame H<sub>2<\/sub>O molaarmassi.<\/span><\/span><\/td>\n<td><i><span lang=\"et\"><span style=\"line-height: 115%;\">M<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 115%;\">(H<sub>2<\/sub>O) = 2 $\\times $ 1 + 16 = 18 g\/mol<\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span lang=\"et\"><span style=\"line-height: 115%;\">8. Leiame H<sub>2<\/sub>O massi.<\/span><\/span><\/td>\n<td><i><span lang=\"et\"><span style=\"line-height: 115%;\">m <\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 115%;\">= <i>n <\/i>$\\times $ <i>M <\/i>= 2 mol $\\times $ 18 g\/mol = 36 g<\/span><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><\/p><div class=\"accordion mb-3\">\n        <div class=\"accordion-item accordion-item--white\">\n        <h2 class=\"accordion-header\" id=\"accordion-69dc48804e4a4-heading\">\n            <button class=\"accordion-button collapsed\" type=\"button\" data-bs-toggle=\"collapse\" data-bs-target=\"#accordion-69dc48804e4a4-collapse\" aria-expanded=\"true\" aria-controls=\"accordion-69dc48804e4a4-collapse\">\u00dclesanne 2<\/button>\n        <\/h2>\n        <div id=\"accordion-69dc48804e4a4-collapse\" class=\"accordion-collapse collapse\" aria-labelledby=\"accordion-69dc48804e4a4-heading\">\n            <div class=\"accordion-body\">\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><div class=\"video-placeholder-wrapper video-placeholder-wrapper--fixed\" style=\"height: 317px;\">\n\t\t\t    <div class=\"video-placeholder d-flex justify-content-center align-items-center\">\n\t\t\t        <div class=\"overlay text-white p-2 w-100 text-center d-block justify-content-center align-items-center\">\n\t\t\t            <div>Kolmandate osapoolte sisu n\u00e4gemiseks palun n\u00f5ustu k\u00fcpsistega.<\/div>\n\t\t\t            <button class=\"btn btn-secondary btn-sm mt-1 consent-change\">Muuda n\u00f5usolekut<\/button>\n\t\t\t        <\/div>\n\t\t\t    <\/div>\n\t\t\t<\/div>\n<script src=\"https:\/\/sisu.ut.ee\/wp-content\/plugins\/h5p\/h5p-php-library\/js\/h5p-resizer.js\" charset=\"UTF-8\"><\/script><\/p><\/div>\n        <\/div>\n        <\/div>\n    <\/div>\n<h2>N\u00e4idis\u00fclesanne 3. Moolilt ruumalale \u00fcleminek<\/h2>\n<table class=\"table table-hover\" style=\"width: 100%;\" border=\"0\" cellspacing=\"1\" cellpadding=\"1\">\n<tbody>\n<tr>\n<td style=\"width: 50%;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">1. Loeme teksti l\u00e4bi ning paneme kirja, et nii vesinik kui ka hapnik on hetkel l\u00e4hteained.<\/span><\/span><\/span><\/td>\n<td>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Mitu kuupdetsimeetrit hapnikku reageerib 3 mol vesinikuga?<\/span><\/span><\/span><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2. Kirjutame ja tasakaalustame tekstile vastava reaktsiooniv\u00f5rrandi.<\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2H<sub>2<\/sub> + O<sub>2<\/sub><\/span><\/span><span lang=\"et\"><span style=\"line-height: 150%;\"> \u2192 2H<\/span><\/span><sub><span lang=\"et\"><span style=\"line-height: 150%;\">2<\/span><\/span><\/sub><span lang=\"et\"><span style=\"line-height: 150%;\">O<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">3. Kirjutame v\u00e4lja andmed ja otsitava.<\/span><\/span><\/span><\/p>\n<\/td>\n<td>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><i><u><span lang=\"et\"><span style=\"line-height: 150%;\">n<\/span><\/span><\/u><\/i><u><span lang=\"et\"><span style=\"line-height: 150%;\">(H<sub>2<\/sub>) = 3 mol<\/span><\/span><\/u><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">V<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">(O<sub>2<\/sub>) = ?<\/span><\/span><\/span><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">4. Antud hetkel on vaja leida \u00fche aine ruumala teise aine moolide j\u00e4rgi. Seega tuleb k\u00f5igepealt leida hapniku moolid, arvestades moolsuhet. <\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Tasakaalustatud reaktsiooniv\u00f5rrandist on n\u00e4ha, et H<sub>2<\/sub> ja O<sub>2<\/sub> moolsuhe on 2:1 ehk hapniku on 2 korda v\u00e4hem. Sellest saame j\u00e4reldada, et <i>n<\/i>(O<sub>2<\/sub>) = 3 mol \/ 2 = 1,5 mol.<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">5. Meie k\u00e4est k\u00fcsiti aga hapniku ruumala. Moolid ja ruumala sidus j\u00e4rgnev valem:<\/span><\/span><\/span><\/td>\n<td>$n=\\frac{V}{V_{m}}$<\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">6. Avaldame valemist ruumala.<\/span><\/span><\/span><\/td>\n<td><i><span lang=\"et\"><span style=\"line-height: 115%;\">V <\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 115%;\">= <i>n <\/i>$\\times $ <i>V<\/i><sub>m<\/sub><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span lang=\"et\"><span style=\"line-height: 115%;\">7. Leiame hapnikku ruumala.<\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">V<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\"> = <i>n <\/i>$\\times $ <i>V<\/i><sub>m<\/sub> = 1,5 mol $\\times $ 22,4 dm<sup>3<\/sup>\/mol = 33,6 dm<sup>3<\/sup><\/span><\/span><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><\/p><div class=\"accordion mb-3\">\n        <div class=\"accordion-item accordion-item--white\">\n        <h2 class=\"accordion-header\" id=\"accordion-69dc48804e4a7-heading\">\n            <button class=\"accordion-button collapsed\" type=\"button\" data-bs-toggle=\"collapse\" data-bs-target=\"#accordion-69dc48804e4a7-collapse\" aria-expanded=\"true\" aria-controls=\"accordion-69dc48804e4a7-collapse\">\u00dclesanne 3<\/button>\n        <\/h2>\n        <div id=\"accordion-69dc48804e4a7-collapse\" class=\"accordion-collapse collapse\" aria-labelledby=\"accordion-69dc48804e4a7-heading\">\n            <div class=\"accordion-body\">\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><div class=\"video-placeholder-wrapper video-placeholder-wrapper--fixed\" style=\"height: 319px;\">\n\t\t\t    <div class=\"video-placeholder d-flex justify-content-center align-items-center\">\n\t\t\t        <div class=\"overlay text-white p-2 w-100 text-center d-block justify-content-center align-items-center\">\n\t\t\t            <div>Kolmandate osapoolte sisu n\u00e4gemiseks palun n\u00f5ustu k\u00fcpsistega.<\/div>\n\t\t\t            <button class=\"btn btn-secondary btn-sm mt-1 consent-change\">Muuda n\u00f5usolekut<\/button>\n\t\t\t        <\/div>\n\t\t\t    <\/div>\n\t\t\t<\/div>\n<script src=\"https:\/\/sisu.ut.ee\/wp-content\/plugins\/h5p\/h5p-php-library\/js\/h5p-resizer.js\" charset=\"UTF-8\"><\/script><\/p><\/div>\n        <\/div>\n        <\/div>\n    <\/div>\n<h2>N\u00e4idis\u00fclesanne 4. Massilt ruumalale \u00fcleminek<\/h2>\n<table class=\"table table-hover\" style=\"width: 100%;\" border=\"0\" cellspacing=\"1\" cellpadding=\"1\">\n<tbody>\n<tr>\n<td style=\"width: 50%;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">1. Loeme teksti l\u00e4bi ning paneme kirja, et nii vesinik kui ka hapnik on hetkel l\u00e4hteained.<\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Mitu kuupdetsimeetrit hapnikku reageerib 6 grammi vesinikuga?<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2. Kirjutame ja tasakaalustame tekstile vastava reaktsiooniv\u00f5rrandi.<\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">2H<sub>2<\/sub> + O<sub>2<\/sub><\/span><\/span><span lang=\"et\"><span style=\"line-height: 150%;\"> \u2192 2H<\/span><\/span><sub><span lang=\"et\"><span style=\"line-height: 150%;\">2<\/span><\/span><\/sub><span lang=\"et\"><span style=\"line-height: 150%;\">O<\/span><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">3. Kirjutame v\u00e4lja andmed ja otsitava.<\/span><\/span><\/span><\/td>\n<td>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><i><u><span lang=\"et\"><span style=\"line-height: 150%;\">m<\/span><\/span><\/u><\/i><u><span lang=\"et\"><span style=\"line-height: 150%;\">(H<sub>2<\/sub>) = 6 g<\/span><\/span><\/u><\/span><\/p>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">V<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">(O<sub>2<\/sub>) = ?<\/span><\/span><\/span><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">4. Siinkohal tuleb meeles pidada, et moolide hulk seob reaktsiooniv\u00f5rrandis kahte ainet omavahel. <\/span><\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Seega tuleb k\u00f5igepealt leida moolide arv ainele, mille kohta algandmetes on infot. Kuna vesiniku mass on antud, saab leida ka vesiniku moolide arvu, kasutades valemit:\u00a0<\/span><\/span><\/span>$n=\\frac{m}{M}$\n<p><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">M<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\">(H<sub>2<\/sub>) = 2 $\\times $ 1 = 2 g\/mol<\/span><\/span><\/span><\/p>\n<p>$n(H_{2})=\\frac{6\\ g}{2\\\u00a0 g\/mol}= 3\\ mol$<\/p><\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">5. Kui me teame vesiniku moolide arvu, saame leida ka hapniku moolide arvu. <\/span><\/span><\/span><\/td>\n<td>\n<p style=\"margin: 12.0pt 0cm 12.0pt 0cm;\"><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">Tasakaalustatud reaktsiooniv\u00f5rrandist on n\u00e4ha, et H<sub>2<\/sub> ja O<sub>2<\/sub> moolsuhe on 2:1 ehk hapniku on 2 korda v\u00e4hem. Sellest saame j\u00e4reldada, et <i>n<\/i>(O<sub>2<\/sub>) = 3 mol \/ 2 = 1,5 mol.<\/span><\/span><\/span><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td><span lang=\"et\"><span style=\"line-height: 115%;\">6. Meie k\u00e4est k\u00fcsiti aga hapniku ruumala. <\/span><\/span><\/td>\n<td><span lang=\"et\"><span style=\"line-height: 115%;\">Moolid ja ruumala sidus j\u00e4rgnev valem:\u00a0<\/span><\/span>$n=\\frac{V}{V_{m}}$<\/td>\n<\/tr>\n<tr>\n<td><span style=\"line-height: 150%;\"><span lang=\"et\"><span style=\"line-height: 150%;\">7. Avaldame valemist ruumala.<\/span><\/span><\/span><\/td>\n<td><i><span lang=\"et\"><span style=\"line-height: 115%;\">V<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 115%;\"> = <i>n <\/i>$\\times $ <i>V<\/i><sub>m<\/sub><\/span><\/span><\/td>\n<\/tr>\n<tr>\n<td><span lang=\"et\"><span style=\"line-height: 115%;\">8. Leiame hapniku ruumala.<\/span><\/span><\/td>\n<td><span style=\"line-height: 150%;\"><i><span lang=\"et\"><span style=\"line-height: 150%;\">V<\/span><\/span><\/i><span lang=\"et\"><span style=\"line-height: 150%;\"> = <i>n<\/i> $\\times $ <i>V<\/i><sub>m<\/sub> = 1,5 mol $\\times $ 22,4 dm<sup>3<\/sup>\/mol = 33,6 dm<sup>3<\/sup><\/span><\/span><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><\/p><div class=\"accordion mb-3\">\n        <div class=\"accordion-item accordion-item--white\">\n        <h2 class=\"accordion-header\" id=\"accordion-69dc48804e4a9-heading\">\n            <button class=\"accordion-button collapsed\" type=\"button\" data-bs-toggle=\"collapse\" data-bs-target=\"#accordion-69dc48804e4a9-collapse\" aria-expanded=\"true\" aria-controls=\"accordion-69dc48804e4a9-collapse\">\u00dclesanne 4<\/button>\n        <\/h2>\n        <div id=\"accordion-69dc48804e4a9-collapse\" class=\"accordion-collapse collapse\" aria-labelledby=\"accordion-69dc48804e4a9-heading\">\n            <div class=\"accordion-body\"><div class=\"video-placeholder-wrapper video-placeholder-wrapper--fixed\" style=\"height: 303px;\">\n\t\t\t    <div class=\"video-placeholder d-flex justify-content-center align-items-center\">\n\t\t\t        <div class=\"overlay text-white p-2 w-100 text-center d-block justify-content-center align-items-center\">\n\t\t\t            <div>Kolmandate osapoolte sisu n\u00e4gemiseks palun n\u00f5ustu k\u00fcpsistega.<\/div>\n\t\t\t            <button class=\"btn btn-secondary btn-sm mt-1 consent-change\">Muuda n\u00f5usolekut<\/button>\n\t\t\t        <\/div>\n\t\t\t    <\/div>\n\t\t\t<\/div>\n<script src=\"https:\/\/sisu.ut.ee\/wp-content\/plugins\/h5p\/h5p-php-library\/js\/h5p-resizer.js\" charset=\"UTF-8\"><\/script><\/div>\n        <\/div>\n        <\/div>\n    <\/div>\n","protected":false},"excerpt":{"rendered":"<p>Keemias tuleb sageli teha arvutusi reaktsiooniv\u00f5rrandite p\u00f5hjal. Selleks tuleks eelnevalt kirjutada rekatsiooniv\u00f5rrand ja see ka tasakaalustada. Reaktsiooniv\u00f5rrandis olevad kordajad n\u00e4itavad reageerivate ja tekkivate ainete hulka moolides. Kuidas reaktsiooniv\u00f5rrandi kordajaid arvutustes kasutada ning milliseid arvutusi reaktsiooniv\u00f5rrandi alusel v\u00f5ib teha, saad vaadata &#8230;<\/p>\n","protected":false},"author":276,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_acf_changed":false,"inline_featured_image":false,"footnotes":""},"class_list":["post-36","page","type-page","status-publish","hentry"],"acf":[],"_links":{"self":[{"href":"https:\/\/sisu.ut.ee\/keemiaabc\/wp-json\/wp\/v2\/pages\/36","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sisu.ut.ee\/keemiaabc\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/sisu.ut.ee\/keemiaabc\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/sisu.ut.ee\/keemiaabc\/wp-json\/wp\/v2\/users\/276"}],"replies":[{"embeddable":true,"href":"https:\/\/sisu.ut.ee\/keemiaabc\/wp-json\/wp\/v2\/comments?post=36"}],"version-history":[{"count":4,"href":"https:\/\/sisu.ut.ee\/keemiaabc\/wp-json\/wp\/v2\/pages\/36\/revisions"}],"predecessor-version":[{"id":601,"href":"https:\/\/sisu.ut.ee\/keemiaabc\/wp-json\/wp\/v2\/pages\/36\/revisions\/601"}],"wp:attachment":[{"href":"https:\/\/sisu.ut.ee\/keemiaabc\/wp-json\/wp\/v2\/media?parent=36"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}